3.422 \(\int (c x)^m \sqrt {a x^j+b x^n} \, dx\)

Optimal. Leaf size=100 \[ \frac {2 x (c x)^m \sqrt {a x^j+b x^n} \, _2F_1\left (-\frac {1}{2},\frac {m+\frac {n}{2}+1}{j-n};\frac {2 m+n+2}{2 j-2 n}+1;-\frac {a x^{j-n}}{b}\right )}{(2 m+n+2) \sqrt {\frac {a x^{j-n}}{b}+1}} \]

[Out]

2*x*(c*x)^m*hypergeom([-1/2, (1+m+1/2*n)/(j-n)],[1+(2+2*m+n)/(2*j-2*n)],-a*x^(j-n)/b)*(a*x^j+b*x^n)^(1/2)/(2+2
*m+n)/(1+a*x^(j-n)/b)^(1/2)

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Rubi [A]  time = 0.09, antiderivative size = 100, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {2032, 365, 364} \[ \frac {2 x (c x)^m \sqrt {a x^j+b x^n} \, _2F_1\left (-\frac {1}{2},\frac {m+\frac {n}{2}+1}{j-n};\frac {2 m+n+2}{2 j-2 n}+1;-\frac {a x^{j-n}}{b}\right )}{(2 m+n+2) \sqrt {\frac {a x^{j-n}}{b}+1}} \]

Antiderivative was successfully verified.

[In]

Int[(c*x)^m*Sqrt[a*x^j + b*x^n],x]

[Out]

(2*x*(c*x)^m*Sqrt[a*x^j + b*x^n]*Hypergeometric2F1[-1/2, (1 + m + n/2)/(j - n), 1 + (2 + 2*m + n)/(2*j - 2*n),
-((a*x^(j - n))/b)])/((2 + 2*m + n)*Sqrt[1 + (a*x^(j - n))/b])

Rule 364

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a^p*(c*x)^(m + 1)*Hypergeometric2F1[-
p, (m + 1)/n, (m + 1)/n + 1, -((b*x^n)/a)])/(c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
(ILtQ[p, 0] || GtQ[a, 0])

Rule 365

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[(a^IntPart[p]*(a + b*x^n)^FracPart[p])
/(1 + (b*x^n)/a)^FracPart[p], Int[(c*x)^m*(1 + (b*x^n)/a)^p, x], x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[
p, 0] &&  !(ILtQ[p, 0] || GtQ[a, 0])

Rule 2032

Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> Dist[(c^IntPart[m]*(c*x)^FracP
art[m]*(a*x^j + b*x^n)^FracPart[p])/(x^(FracPart[m] + j*FracPart[p])*(a + b*x^(n - j))^FracPart[p]), Int[x^(m
+ j*p)*(a + b*x^(n - j))^p, x], x] /; FreeQ[{a, b, c, j, m, n, p}, x] &&  !IntegerQ[p] && NeQ[n, j] && PosQ[n
- j]

Rubi steps

\begin {align*} \int (c x)^m \sqrt {a x^j+b x^n} \, dx &=\frac {\left (x^{-m-\frac {n}{2}} (c x)^m \sqrt {a x^j+b x^n}\right ) \int x^{m+\frac {n}{2}} \sqrt {b+a x^{j-n}} \, dx}{\sqrt {b+a x^{j-n}}}\\ &=\frac {\left (x^{-m-\frac {n}{2}} (c x)^m \sqrt {a x^j+b x^n}\right ) \int x^{m+\frac {n}{2}} \sqrt {1+\frac {a x^{j-n}}{b}} \, dx}{\sqrt {1+\frac {a x^{j-n}}{b}}}\\ &=\frac {2 x (c x)^m \sqrt {a x^j+b x^n} \, _2F_1\left (-\frac {1}{2},\frac {1+m+\frac {n}{2}}{j-n};1+\frac {2+2 m+n}{2 j-2 n};-\frac {a x^{j-n}}{b}\right )}{(2+2 m+n) \sqrt {1+\frac {a x^{j-n}}{b}}}\\ \end {align*}

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Mathematica [A]  time = 0.21, size = 156, normalized size = 1.56 \[ \frac {2 x (c x)^m \left ((2 j+2 m-n+2) \left (a x^j+b x^n\right )-a (j-n) x^j \sqrt {\frac {a x^{j-n}}{b}+1} \, _2F_1\left (\frac {1}{2},\frac {2 j+2 m-n+2}{2 j-2 n};\frac {4 j+2 m-3 n+2}{2 j-2 n};-\frac {a x^{j-n}}{b}\right )\right )}{(2 m+n+2) (2 j+2 m-n+2) \sqrt {a x^j+b x^n}} \]

Antiderivative was successfully verified.

[In]

Integrate[(c*x)^m*Sqrt[a*x^j + b*x^n],x]

[Out]

(2*x*(c*x)^m*((2 + 2*j + 2*m - n)*(a*x^j + b*x^n) - a*(j - n)*x^j*Sqrt[1 + (a*x^(j - n))/b]*Hypergeometric2F1[
1/2, (2 + 2*j + 2*m - n)/(2*j - 2*n), (2 + 4*j + 2*m - 3*n)/(2*j - 2*n), -((a*x^(j - n))/b)]))/((2 + 2*j + 2*m
- n)*(2 + 2*m + n)*Sqrt[a*x^j + b*x^n])

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fricas [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^m*(a*x^j+b*x^n)^(1/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (ha
s polynomial part)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {a x^{j} + b x^{n}} \left (c x\right )^{m}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^m*(a*x^j+b*x^n)^(1/2),x, algorithm="giac")

[Out]

integrate(sqrt(a*x^j + b*x^n)*(c*x)^m, x)

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maple [F]  time = 0.84, size = 0, normalized size = 0.00 \[ \int \sqrt {a \,x^{j}+b \,x^{n}}\, \left (c x \right )^{m}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x)^m*(a*x^j+b*x^n)^(1/2),x)

[Out]

int((c*x)^m*(a*x^j+b*x^n)^(1/2),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {a x^{j} + b x^{n}} \left (c x\right )^{m}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^m*(a*x^j+b*x^n)^(1/2),x, algorithm="maxima")

[Out]

integrate(sqrt(a*x^j + b*x^n)*(c*x)^m, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int {\left (c\,x\right )}^m\,\sqrt {a\,x^j+b\,x^n} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x)^m*(a*x^j + b*x^n)^(1/2),x)

[Out]

int((c*x)^m*(a*x^j + b*x^n)^(1/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (c x\right )^{m} \sqrt {a x^{j} + b x^{n}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)**m*(a*x**j+b*x**n)**(1/2),x)

[Out]

Integral((c*x)**m*sqrt(a*x**j + b*x**n), x)

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